WebJun 17, 2024 · If there is no value returned by the end of the loop, return false because there must not be a value that appears twice in the array. class Solution: def containsDuplicate (self, nums: List [int ... Webclass Solution (object): def findPeakElement (self, nums): """ :type nums: List[int] :rtype: int """ size = len (nums) for x in range (1, size -1): if nums [x] > nums [x -1] and nums [x] > nums [x + 1]: return x return [0, size -1] [nums [0] < nums [size -1]] ##That last row is an obscure way of writing an if then else expression. ## [0, size-1 ...
Monotonic Array - DEV Community 👩💻👨💻
WebJan 10, 2024 · View TovAm's solution of Monotonic Array on LeetCode, the world's largest programming community. Webclass Solution: def isMonotonic(self, nums: List[int]) -> bool: return self.monotonic(nums, lambda x, y: x <= y) or self.monotonic( nums, lambda x, y: x >= y ) def monotonic(self, nums, f): for i in range(1, len(nums)): if not f(nums[i - 1], nums[i]): … tempolan
Leetcode Search in Rotated Sorted Array II problem solution
WebThis repository contains my solutions to questions on Leetcode along with time and space complexity breakdowns - Leetcode-Solutions/problem_896_monotonic_array.py at ... WebApr 10, 2024 · 617. 合并二叉树 - 力扣(LeetCode). 确定递归函数的参数和返回值 : 确定哪些参数是递归的过程中需要处理的,那么就在递归函数里加上这个参数, 并且还要明确每次递归的返回值是什么进而确定递归函数的返回类型。. 确定终止条件 : 写完了递归算法, 运 … WebThe way it works is: Sort nums. Create two pointers representing an index at 0 and an index at len (nums) - 1. Sum the elements at the pointers. If they produce the desired sum, return the pointer indices. Otherwise, if the sum is less than the target, increment the left pointer. Otherwise, decrement the right pointer. tempo lagu yang berarti sangat cepat adalah